Another random 'division' problem using the Obelus

I found this one in particular on Facebook:

Let me make this one clear very fast.  This statement does not contain your conventional division sign in it.  It contains an obelus in it.  Let us do this following the rules of algebra, but not only this, show how this problem works out if you do this the correct way most are not taught, and the way they are interpreting it.  

(1: the proper way if we assume obelus is a binary operator with two arguments, refer to my post about the obelus for more about this):
6-1x0+2(obelus)2, becomes 6-0+2 (obelus) 2, becomes 8 (obelus) 2, which is 4.  

(2: the same method, except doing the proper substitution)
(6-1x0+2)/(2), becomes (8)/(2), which is 4.

(3: the way people do it when they interpret the obelus as the full blown division operator)
6-1x0+2/2, becomes after multiplication 6-0+2/2, becomes after division 6-0+1, becomes 6+1, which is 7.

Enjoy!  Have a beautiful day!


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